TickTock
Well-known member
- Joined
- Jul 27, 2023
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- Phoenix, AZ
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- `11 Nissan Leaf; '18 Model 3; '18 Model S; '24 Beast
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- Electrical Engineer
OK. Adjusting again. :-}I realized that for the outer wheel to get the full benefit of 10 degrees, the inner wheel would have to turn *more* than 10 degrees. Since 10 is the max and both wheels are controlled by the same linkage I think it is more accurate to compute based on the centerline of the truck. This means the vector of the rear of the truck is effectively the average of the outer and the inner when both are 10 degrees. The number, computed this way, comes to 39ft.43.5ft (13.26m) current turning radius
What would the turning radius be if it was 10 degrees? Asking too much?![]()
- Construct a triangle from the point between the front ties, point between rear tires and the center of rotation per the diagram. C is center of front; B is center of rear; and A is center of the circle. Distance c is half of the current turning circle (21.75ft) minus half the width of the truck (3.325ft) = 18.425 ft ; b is distance between wheels (12.5ft); γ is the rear wheel angle (currently 90-3=87 degrees)
- Given the values from step 1, solve for a (distance from rear wheel to center) using the Law of Cosines (shown above the diagram). --> a=14.2 ft
- Now, using the same formula, but at point C solve for the front steering angle α. α=50.35 degrees
- Calculate the angle β. 180-87-50.35=42.65 degrees with the current 3 degree rear wheel steer.
- Increasing rear steer to 10 degrees makes β 180-80-50.35=49.65 degrees
- Now using the Law of Sines, calculate the new distance c to the center of the front inner wheels. c/sin(γ)=b/sin(β) --> c=16.15 ft --> add half the truck width back in and double to get the new turning circle of 38.95ft (=2*(16.15+3.325))
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