HaulingAss
Well-known member
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- Oct 3, 2020
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- Cybertruck DM, 2010 F-150, 2018 Performance Model 3, 2024 Performance Model 3
Exactly. And if the total "flex" is only .7 inch, then you've hit 200,000 lbs, and so on.This is akin to hitting a nail with a hammer. Much higher force than just pushing on the nail with the hammer, but how much higher?
If Cybertruck dropped 1 meter, that's a time of 0.45 seconds and final velocity of 4.41 m/s.
Acceleration required to stop the vehicle depends on the time the deceleration happens. If the back half is 3,500 pounds, then you hit 100,000 pounds if it takes 28.6gs. Knock one off for Earth and you get 27.6gs
27.6*9.8 = 270.48 m/s²
4.41 m/s / 270 m/s² = 0.016 s or 16 milliseconds
Assuming constant deceleration (unlikely, but easier) distance traveled = 0.016*4.41 -0.5*270*(0.016)² = 0.036m = 3.6cm = 1.4 inches
So, if the body and block flex less than 1.4 inches on impact (or drop is higher, or deceleration is nonlinear), then it would reach 100,000 pounds.
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