Diehard
Well-known member
- First Name
- D
- Joined
- Dec 5, 2020
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- U.S.A.
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- Olds Aurora V8, Saturn Sky redline, Lightning, CT2
I think you solved for the wrong V. This is my calculation:D,
Regarding turbulence, it is not that simple. As some of us discussed, there are devices called "VGs" or Vortex Generators. They intentionally create little vortexes, or "tornados". That is "turbulence" or energized airflow. But this energy allows the air to flow over a surface that it wouldn't be able to follow without it. Do they cause some level of drag? Yep! But the small amount they cause is offset by the additional lift, or elimination of drag to a much larger area. Again, look at a modern F1 car. They have little curved spikes all over the car. They are there to manage the airflow either away from something, or towards something, or to keep the flow attached to a surface for one reason. Golf balls are the greatest common example of "a little turbulence is a good thing". Take the turbulence from the dimples away, and you can't get the ball to travel anywhere near as far. Or to put it in more grasp-able terms, I still can't hit a dimpled ball as far as John Daly could hit a smooth ball, but a serious golfer could.
As for your cd truck comparison, assuming all else is equal (tires, size, temp, rolling resistance, etc) this is what I get...
Fair=0.5∗Cd∗A∗rho∗V2
Where:
Fair is the air resistance force (the force that opposes the motion of the truck).
Cd is the coefficient of drag (0.46 for one truck and 0.3 for the other).
A is the frontal area of the truck.
rho is the air density.
V is the velocity of the truck. (V2 is "Squared")
Off the top of my head, and only 1/2 way through my coffee after flying through 9 time zones yesterday, this is the equation;
0.5∗0.46∗A∗rho∗(802)=0.5∗0.3∗A∗rho∗(80−x)2
(again, the little 2 means squared)
Since I let the app do my math due to my severe lack of caffeination and extreme laziness, I get;
x≈−24.71
Meaning that the 0.30cd going 80 has roughly the same drag as the .46cd doing 55.29.
0.5∗0.46∗A∗rho∗Vsq=0.5∗0.3∗A∗rho∗(80sq)
0.46∗Vsq=0.3∗(80sq)
Vsq=1920/0.46
V= 64.6
I am not saying turbulence can not be helpful. Just saying I doubt that flat surface in the back window area was intentional to help drag coefficient. Lets see if next generation Aptera comes with dimples.
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